Question 1183648: The quality assurance engineer of a receiving-sets manufacturer inspects receiving-sets in lots of 50. He selects 4 of the 50 receiving-sets at random and inspects them thoroughly. Assuming that 5 of the 50 receiving-sets in the current lot are defective, find the probability that exactly 3 of the 4 receiving-sets selected by the engineer are defective.
Answer by ikleyn(52884) (Show Source):
You can put this solution on YOUR website! .
The quality assurance engineer of a receiving-sets manufacturer inspects receiving-sets in lots of 50.
He selects 4 of the 50 receiving-sets at random and inspects them thoroughly.
Assuming that 5 of the 50 receiving-sets in the current lot are defective, find the probability
that exactly 3 of the 4 receiving-sets selected by the engineer are defective.
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P = = = = = 0.001954. ANSWER
The numerator of P, , is the number of favorable combinations of 4 of the 50 receiving-sets,
that contain exactly 3 defective receiving-sets and one good receiving-set.
It is the favorable set.
The denominator is the total number of 4 receiving-sets selected by the engineer from 50 receiving-sets.
The probability, as always in such problem, is the ratio .
Solved.
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- Elementary Probability problems related to combinations
- Elementary Probability problems related to combinations REVISITED
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