SOLUTION: The quality assurance engineer of a receiving-sets manufacturer inspects receiving-sets in lots of 50. He selects 4 of the 50 receiving-sets at random and inspects them thoroughly.

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Question 1183648: The quality assurance engineer of a receiving-sets manufacturer inspects receiving-sets in lots of 50. He selects 4 of the 50 receiving-sets at random and inspects them thoroughly. Assuming that 5 of the 50 receiving-sets in the current lot are defective, find the probability that exactly 3 of the 4 receiving-sets selected by the engineer are defective.
Answer by ikleyn(52884) About Me  (Show Source):
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The quality assurance engineer of a receiving-sets manufacturer inspects receiving-sets in lots of 50.
He selects 4 of the 50 receiving-sets at random and inspects them thoroughly.
Assuming that 5 of the 50 receiving-sets in the current lot are defective, find the probability
that exactly 3 of the 4 receiving-sets selected by the engineer are defective.
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P = %28C%5B5%5D%5E3%2AC%5B50-5%5D%5E1%29%2FC%5B50%5D%5E4 = %28C%5B5%5D%5E3%2AC%5B45%5D%5E1%29%2FC%5B50%5D%5E4 = %2810%2A45%29%2F230300 = 9%2F4606 = 0.001954.      ANSWER



The numerator of P,  C%5B5%5D%5E3%2AC%5B45%5D%5E1,  is the number of favorable combinations of 4 of the 50 receiving-sets, 
that contain exactly 3 defective receiving-sets and one good receiving-set.


It is the favorable set.


The denominator is the total number of 4 receiving-sets selected by the engineer from 50 receiving-sets.


The probability, as always in such problem, is the ratio  favorable%2Ftotal.

Solved.

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