SOLUTION: I have 24 options to choose from, and 4 of those are big prices. I got 20 attempts. 1. What is the probability of getting at least 1 big win in 20 attempts, without replacement

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Question 1183619: I have 24 options to choose from, and 4 of those are big prices. I got 20 attempts.
1. What is the probability of getting at least 1 big win in 20 attempts, without replacement?
I thought that it would be C4 1/C24 20, but this was wrong. So I don't know what to do. I got confused, and now I can't get through the next one either.
2. What is the probability of getting all 4 in 20 attempts?

Found 2 solutions by ikleyn, robertb:
Answer by ikleyn(52781) About Me  (Show Source):
You can put this solution on YOUR website!
.

From your post,  it is  UNCLEAR,  what your attempts are.


When a probabilistic problem is formulated,  the key part of its formulation is a precise
and accurate description of the probabilistic experiment.


In your post,  this description is simply  ABSENTS,  making the entire problem nonsensical.


///////////


From the post,  it is clear that the problem is not from a textbook --- it is your attempt to create your own problem.


Creating new problem is an   A R T.   It requires knowledge of the subject,  familiarity
with existing problems and existing standards,  to be a master in using language and terminology,  etc.


From your post,  it is clear that you have no that level of knowledge and experience to compose new problems on your own.

Read and learn from textbooks and from other available/existing sources in the Internet.


Happy learning  ( ! )



Answer by robertb(5830) About Me  (Show Source):
You can put this solution on YOUR website!
1. P(at least one big prize) = 1 - P(no big prize).
Now P(no big prize) =

Hence P(at least one big prize) = 1+-+1%2F10626+=+highlight%280.999906%29 to 6 d.p., which is virtually 1.
In other words, with 20 attempts you almost surely will have at least one big win, or one big prize, however you want to call it.

2. P(all big prizes) = ~ 0.455957 to 6 d.p.