Question 1183594: A coin purse contains 5 cents, 10 cents and 25 cents coins. The number of 10 cents-coins is three times as many as 5 cents-coin, and the 25 cents-coin is two more than the 10 cent-coin. If the total value of its contents isP4.90, how many of each kind of coins are in the purse?
Answer by ikleyn(52756)   (Show Source):
You can put this solution on YOUR website! .
A coin purse contains 5 cents, 10 cents and 25 cents coins.
The number of 10 cents-coins is three times as many as 5 cents-coin,
and the 25 cents-coin is two more than the 10 cent-coin.
If the total value of its contents isP4.90, how many of each kind of coins are in the purse?
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It is a typical problem to be solved using only one unknown.
Let x be the number of 5-cent coins.
Then the number of 10 cent coins is 3x, according to the condition,
and the number of 25-cent coins is 3x+2 coins.
Now we write the total money equation
5x + 10*(3x) + 25*(3x+2) = 490 cents.
Now simplify and find x
5x + 30x + 75x + 50 = 490
110x = 490 - 50 = 440
x = 440/110 = 4.
ANSWER. 4 5-cent coins; 4*3 = 12 10-cent coins and 12+2 = 14 25-cent coins.
CHECK. 4*5 + 12*10 + 14*25 = 490 cents. (!) Precisely correct (!)
Solved.
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