SOLUTION: Given f(x) = cos x and g(x) = 𝜋x, evaluate each expression. f(g(2))= f(g(1/2))= g(f(0))= g(f(𝜋/4))= f(g(x))= g(f(x))=

Algebra ->  Trigonometry-basics -> SOLUTION: Given f(x) = cos x and g(x) = 𝜋x, evaluate each expression. f(g(2))= f(g(1/2))= g(f(0))= g(f(𝜋/4))= f(g(x))= g(f(x))=       Log On


   

Question 1183588: Given f(x) = cos x and g(x) = 𝜋x, evaluate each expression.
f(g(2))=
f(g(1/2))=
g(f(0))=
g(f(𝜋/4))=
f(g(x))=
g(f(x))=






Found 2 solutions by ikleyn, MathLover1:
Answer by ikleyn(52805) About Me  (Show Source):
You can put this solution on YOUR website!
.

If you can not solve any single task from this list on your own, then you are in wrong class.



Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

f%28x%29+=+cos+%28x%29+and g%28x%29+=+pi%2Ax
evaluate each expression:
+f%28g%28x%29%29
f%28g%28x%29%29=f%28pi%2Ax%29=cos%28pi%2Ax%29

f%28g%282%29%29=cos%28pi%2A2%29
f%28g%282%29%29=cos%282pi%29
f%28g%282%29%29=1

f%28g%281%2F2%29%29=cos%28pi%2A%281%2F2%29%29
f%28g%281%2F2%29%29=cos%28pi%2F2%29
f%28g%281%2F2%29%29=0


g%28f%28x%29%29
g%28f%28x%29%29=g%28cos%28x%29%29=+pi%2Acos%28x%29

g%28f%280%29%29=+pi%2Acos%280%29
g%28f%280%29%29=+pi%2A1
g%28f%280%29%29=+pi

g%28f%28pi%2F4%29%29=pi%2Acos%28pi%2F4%29
g%28f%28pi%2F4%29%29=pi%2A%281%2Fsqrt%282%29%29
g%28f%28pi%2F4%29%29=pi%2Fsqrt%282%29
g%28f%28pi%2F4%29%29=%28pi%2Asqrt%282%29%29%2F2