SOLUTION: The cost of renting a car is $45 /wk plus $0.25 /mi traveled during that week. An equation to represent the cost would be y=45+0.25x , where x is the number of miles traveled.
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-> SOLUTION: The cost of renting a car is $45 /wk plus $0.25 /mi traveled during that week. An equation to represent the cost would be y=45+0.25x , where x is the number of miles traveled.
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Question 1183511: The cost of renting a car is $45 /wk plus $0.25 /mi traveled during that week. An equation to represent the cost would be y=45+0.25x , where x is the number of miles traveled.
a. What is your cost if you travel 55 mi?
The cost is $
b. If your cost was $66.00 , how many miles were you charged for traveling?
You were charged for traveling
Number
miles.
c. Suppose you have a maximum of $100 to spend for the car rental. What would be the maximum number of miles you could travel?
The maximum number of miles you could travel is
Number
. Answer by Theo(13342) (Show Source):
You can put this solution on YOUR website! the cost is given by the equation y = 45 + .25 * x
y is the total cost.
x is the number of miles traveled.
if you travel 55 miles, the equation becomes y = 45 + .25 * 55.
the total cost is then y = 58.75.
if your cost was 66 dollars, the eqution becomes 66 = 45 + .25 * x.
subtract 45 from both sides of the equation to get:
21 = .25 * x.
divide both sides of the equation by .25 to get:
21 / .25 = x
solve for x to get:
x = 84 miles.
if you have a maximum of 100 dollars to spend for the rental, the equation becomes an inequality which becomes 100 >= 45 + .25 * x.
subtract 45 from both sid3es of the equation to get:
55 >= .25 * x
divide both sides of the inequality by .25 to get:
220 >= x.
this says you can drive up to 220 miles if all you have to spend is 100 dollars.
you could drive less, but that's the maximum number of miles you could drive.
if you rent a car and don't travel any miles, the cost will be 45 dollars.
the following graph shows all these possibilities.