SOLUTION: A hunter bring down 75% of a rabbit he shoot at .what is the probability that at least 3 of the next five rabbit shot will escape

It is a binomial distribution probability type problem.

    - number of trials         n =  5;
    - number of success trials k >= 3;
    - Probability of success on a single trial p = 0.25 = 1 - 0.75  (the probability for a single rabbit to escape).



We need calculate  P(n=5; k>=3; p=0.25).      


To facilitate calculations, I use an appropriate online (free of charge) calculator at this web-site 

https://stattrek.com/online-calculator/binomial.aspx


It provides nice instructions  and  a convenient input and output for all relevant options/cases.


    P(n=5; k>=3; p=0.25) = 0.1035    (rounded).       ANSWER