SOLUTION: Hi A store owner has a pound of a mixture of nuts that is 90% peanuts and 10% Brazil nuts by weight. How much weight in Brazil nuts must be added to make the mixture 75% peanuts.

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Question 1183489: Hi
A store owner has a pound of a mixture of nuts that is 90% peanuts and 10% Brazil nuts by weight. How much weight in Brazil nuts must be added to make the mixture 75% peanuts.
Thanks
Found 2 solutions by josgarithmetic, greenestamps:
Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
b mass units of Brazil Nuts to add.

Assuming some 100 units of original mixture,
and understanding the resulting mixture is expected to be 25% Brazil nuts,

%280.10%2A100%2Bb%29%2F%28b%2B100%29=0.25
.
.

Answer by greenestamps(13203) About Me  (Show Source):
You can put this solution on YOUR website!


As a fraction, the part of the original mixture that is peanuts is %28.9%29%2F%281%29

After additional amount x of Brazil nuts is added to the mixture, the fraction that is peanuts is %28.9%29%2F%281%2Bx%29

The fraction of the mixture that is peanuts is now 3/4:

%28.9%29%2F%281%2Bx%29+=+3%2F4
3x%2B3+=+3.6
3x+=+0.6
x+=+0.2

ANSWER: 0.2 pounds of Brazil nuts must be added to make the mixture 75% peanuts.