SOLUTION: Let R be the region between the 𝑥-axis and the graph of y = 8/(x+1) for x>0. Let S1 be the solid obtained by revolving R around the x-axis. Let S2 be the solid obtained by revol
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-> SOLUTION: Let R be the region between the 𝑥-axis and the graph of y = 8/(x+1) for x>0. Let S1 be the solid obtained by revolving R around the x-axis. Let S2 be the solid obtained by revol
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Question 1183478: Let R be the region between the 𝑥-axis and the graph of y = 8/(x+1) for x>0. Let S1 be the solid obtained by revolving R around the x-axis. Let S2 be the solid obtained by revolving R around the y-axis.
a.Compute the area of R using an improper integral. (my answer: diverges)
b.Compute the volume of S1 using an improper integral. (my answer, using cylinder method: 64pi)
d.Compute the volume of S2 using an improper integral. (my answer, using cylindrical shell method: diverges)
Are these answers correct? Answer by robertb(5830) (Show Source):
You can put this solution on YOUR website! a. Your answer is correct, although you have to mention that the value of the integral is .
b. Your answer for the volume of S1 is correct (), by using the cylindrical disc method.
c. Your answer is correct, although you have to mention that the value of the integral is (using the cylindrical shell method).