SOLUTION: An urn contains 3 red balls, 2 white balls and 1 blue ball. Two balls are drawn without replacement. Let A be the event that at least one ball is red, and B be the event that 2 bal

Algebra ->  Probability-and-statistics -> SOLUTION: An urn contains 3 red balls, 2 white balls and 1 blue ball. Two balls are drawn without replacement. Let A be the event that at least one ball is red, and B be the event that 2 bal      Log On


   



Question 1183446: An urn contains 3 red balls, 2 white balls and 1 blue ball. Two balls are drawn without replacement. Let A be the event that at least one ball is red, and B be the event that 2 balls are of different colours.
What is p(A)?
What is p(A|B)
Are events A and B independent?

Found 2 solutions by ikleyn, robertb:
Answer by ikleyn(52879) About Me  (Show Source):
You can put this solution on YOUR website!
.
An urn contains 3 red balls, 2 white balls and 1 blue ball. Two balls are drawn without replacement.
Let A be the event that at least one ball is red, and B be the event that 2 balls are of different colours.
(a) What is p(A)?
(b) What is p(A|B)
(c) Are events A and B independent?
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(a)  Event A is this set of outcomes  { (R,W), (W,R), (R,B), (B,R), (R,R) }.


         P(A) =  = 


              = %283%2A2+%2B+2%2A3+%2B+3%2A1+%2B+1%2A3+%2B+6%29%2F30 = 24%2F30 = 4%2F5.



(b)  Event B is this set  { (R,W), (W,R), (R,B), (B,R), (W,B), (B,W) }.


         P(B) =  = 


              = %283%2A2+%2B+2%2A3+%2B+3%2A1+%2B+1%2A3+%2B+2%2A1+%2B+1%2A2%29%2F30 = 22%2F30 = 11%2F15.



     The intersection (A and B) is this set  { (R,W), (W,R), (R,B), (B,R) }.


     P(A and B) =  = 


              = %283%2A2+%2B+2%2A3+%2B+3%2A1+%2B+1%2A3%29%2F30 = 18%2F30 = 3%2F5.


     THEREFORE,  P(A|B) = P%28A_and_B%29%2FP%28B%29 = %28%2818%2F30%29%29%2F%28%2822%2F30%29%29 = 18%2F22 = 9%2F11.    ANSWER



(c)  To answer last question, check if P(A and B) is equal to P(A)*P(B).

Solved.



Answer by robertb(5830) About Me  (Show Source):
You can put this solution on YOUR website!


==> P%28A%29+=+1+-+P%28not+A%29+=+1-1%2F5+=+4%2F5



==> P(A|B) = P%28A%2AB%29%2FP%28B%29+=+%283%2F5%29%2F%2811%2F15%29+=+9%2F11
Since P%28A%29%2AP%28B%29+=+%284%2F5%29%2A%2811%2F15%29+%3C%3E3%2F5+=+P%28A%2AB%29, A and B are not independent events.