Question 1183431: Three yam tubers are chosen at random from 15 tubers of which 5 are spoilt. Find the probability that,of the three chosen tubers:
A. None is spoilt
B. All are spoilt
C. Exactly one is spoilt
D. At least one is spoilt.
Found 3 solutions by greenestamps, ikleyn, robertb:
Answer by greenestamps(13330)   (Show Source):
Answer by ikleyn(53751)  (Show Source):
You can put this solution on YOUR website! .
Three yam tubers are chosen at random from 15 tubers of which 5 are spoilt. Find the probability that, of the three chosen tubers:
A. None is spoilt
B. All are spoilt
C. Exactly one is spoilt
D. At least one is spoilt.
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(A) In part (A), you chose, actually, 3 tubers from 10 tubers that are not spoilt, among the total of 15 tubers.
Therefore, you can use any of two formulas to find the probability
P =  =  =  = 0.2637 (rounded),
or
P =  =  = = 0.2637 (same as above).
(B) In part (B), you select, actually, 3 tubers from 5 spoilt tubers, among the total 15 tubers.
Therefore, you can use any of two formulas to find the probability
P =  =  =  = 0.0219 (rounded),
or
P =  =  = = 0.0219 (the same value).
(C) "Exactly one is spoilt" means one is spoilt of the 3 selected among the total 15, and 2 are not.
Therefore, you can use this formula to find the probability
P =  =  =  = 0.4945. (rounded)
(D) It is the complement probability to the value found in (A)
P = 1 - 0.2637 = 0.7363 (rounded).
Solved. // All question are answered.
Answer by robertb(5830)  (Show Source):
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