SOLUTION: Given that a= 2i+3j-k, b=i-j+2k and c= 3i+4j+k, find a +2b - c? Find the area of parallelogram with verticies: (1,1,1), (4,4,4), (8,-3,14) and (11,0,17).

Algebra ->  Parallelograms -> SOLUTION: Given that a= 2i+3j-k, b=i-j+2k and c= 3i+4j+k, find a +2b - c? Find the area of parallelogram with verticies: (1,1,1), (4,4,4), (8,-3,14) and (11,0,17).      Log On


   

Question 1183430: Given that a= 2i+3j-k, b=i-j+2k and c= 3i+4j+k, find a +2b - c?
Find the area of parallelogram with verticies: (1,1,1), (4,4,4), (8,-3,14) and (11,0,17).
Answer by robertb(5830) About Me  (Show Source):
You can put this solution on YOUR website!
The area of the parallelogram is just the magnitude of the cross product of the vectors spanning the parallelogram.
The vector from the point (1,1,1) to (4,4,4) is <3,3,3>. The vector from (1,1,1) to (8,-3, 14) is <7,-4,13>. Hence the area of the parallelogram is

, to 2 d.p.