SOLUTION: The remainder when ax^3 + bx^2 + 2x + 3 is divided by x-1 is twice that when it is divided by x+1. Show that b = 3a + 3
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Question 1183399: The remainder when ax^3 + bx^2 + 2x + 3 is divided by x-1 is twice that when it is divided by x+1. Show that b = 3a + 3 Answer by robertb(5830) (Show Source):
You can put this solution on YOUR website! if , then by the remainder theorem, the remainder upon division of by is equal to .
Similarly, the remainder upon division of by is equal to .
From the given, , hence
==> .
