SOLUTION: The expression 6x^2 - 2x + 3 leaves a remainder of 3 when divided by x - p. Determine the values of p.

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Question 1183386: The expression 6x^2 - 2x + 3 leaves a remainder of 3 when divided by x - p. Determine the values of p.
Found 2 solutions by Solver92311, mananth:
Answer by Solver92311(821) About Me  (Show Source):
You can put this solution on YOUR website!


If is divided by leaving a remainder of , then

So solve


John

My calculator said it, I believe it, that settles it

From
I > Ø

Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
6x^2 - 2x + 3 leaves a remainder of 3 when divided by x - p. Determine the values of p.
f%29x%29+=+6x%5E2+-2x%2B3
divisor = x-p
f(p) = 6p^2-2p+3
By remainder theorem f(p) =remainder= 3
6p%5E2-2p%2B3=3+
6p%5E2-2p=0
2p(3p-1)=0
p= 0 or 1/3