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Question 1183253: According to a well-known statistic theorem, of patients enter a medical clinic at a rate of m patients per minutes and each stays at the clinic an average of W minutes, the average number of patients, L, in the clinic at any point in time is given by L=mW.
The manager of the Kind Care clinic estimates that when the clinic is open, an average of 4 patients per minute enter the clinic and that on average, each of them stays 45 minutes. The manager uses the above theorem to estimate that at any point in time, there are 180 patients in the clinic.
A rival clinic, the Speedy Care Clinic, recently opened across the street. The manager of this clinic estimates that when the clinic is open, an average of 324 patients enter the clinic per hour and that, on average, each of them stays for 40 minutes. The average number of patients at the Speedy Care clinic at any time is what percentage of the average number of patients at the Kind Care clinic at any time?
Answer by ikleyn(52805) (Show Source):
You can put this solution on YOUR website! .
For the rival clinics, the value of m is = 5.4 person per minute; W = 40 minutes;
so the product mW for this rival clinics is 5.4*40 = 216.
Now you are in position to answer the problem's question
percentage = = 120% (rounded).
Solved.
This problem only SEEMS to be complicated; in reality, it is as simple as 1 + 2 = 3.
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