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solve 7cos(4x)=5 for the smallest three positive solutions.
Give answer accurate to at least two decimal places as a list separated by commas.
can someone please help me better understand how to do this problem please
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Your starting equation is
7cos(4x) = 5. (1)
As you understand, it is EQUIVALENT to
cos(4x) =
. (2)
From (2), you have these two series of solutions
4x =
+
= 0.775193 +
(3)
and
4x =
+
=
+
, (4)
where n = 0, +/-1, +/-2, +/-3, +/-4, . . . is any integer number.
From (3), dividing both its sides by 4, you have
x = 0.193798 +
= 0.193798 +
.
First four positive values for n= 0, 1, 2 and 3 are (rounded to 4 decimals) x = 0.1938, 1.7646, 3.3354, 4.9062. (5)
From (4), dividing both its sides by 4, you have
x = 1.3770 +
= 1.3770 +
.
First four positive values for n= 0, 1, 2 and 3 are (rounded to 4 decimals) x = 1.3770, 2.9478, 4.5186, 6.0894. (6)
Now your last step is to select three smallest numbers of 8 numbers of (5) and (6).
Doing this way, you obtain the ANSWER 0.1938, 1.3770, and 1.7646.
Solved.