SOLUTION: Use substitution to solve Drew has a coin jar with a small collection of nickels and dimes. There are 148 coins in the jar. They have a value of $13.20. How many nickels and d

Algebra ->  Customizable Word Problem Solvers  -> Evaluation -> SOLUTION: Use substitution to solve Drew has a coin jar with a small collection of nickels and dimes. There are 148 coins in the jar. They have a value of $13.20. How many nickels and d      Log On

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Question 1183138: Use substitution to solve

Drew has a coin jar with a small collection of nickels and dimes. There are 148 coins in the jar. They have a value of $13.20. How many nickels and dimes are in the jar?

Answer by ikleyn(52887) About Me  (Show Source):
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Use substitution to solve
Drew has a coin jar with a small collection of nickels and dimes. There are 148 coins in the jar.
They have a value of $13.20. How many nickels and dimes are in the jar?
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Let x be the number of nickels and y be the number of dimes.


Write the system of equations as you read the problem

     x +   y =   148      (1)   (total coins)

    5x + 10y = 1320      (2)    (total cents)



From equation (1), express  x = 148-y  and substitute it into equation (2), replacing x there

    5(148-y) + 10*y = 1320.



Simplify

    5*148 - 5y + 10y = 1320

            5y       = 1320 - 5*148

            5y       =     580

             y       =     580/5 = 116.



So, there are 116 dimes.

From equation (1),  the number of nickels is  x = 148 - 116 = 32.



ANSWER.  32 nickels and  116 dimes.


CHECK.  32*5 + 116*10 = 1320  cents, in total.    ! Correct !

Solved.