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How much heat energy does it take to boil 2.35 kg of water at 100oC completely to steam at 100oC
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Here the temperature is the same of 100°C.
Only latent heat of vaporization of steam is required to convert water to steam
Q = m * L
where m is the mass of water = 2.35 kg;
L is the latent heat of vaporization = 2257 kJ/kg
The required heat energy = 2.35 * 2267 = 5327.45 kJ. ANSWER
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