SOLUTION: Find the solutions of the equation cos 2x + cos 𝑥 + 1 = 0 in the interval [0, 2𝜋).

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Question 1183076: Find the solutions of the equation cos 2x + cos 𝑥 + 1 = 0 in the interval [0, 2𝜋).
Found 2 solutions by ikleyn, Solver92311:
Answer by ikleyn(52805) About Me  (Show Source):
You can put this solution on YOUR website!
.
Find the solutions of the equation cos 2x + cos 𝑥 + 1 = 0 in the interval [0, 2𝜋).
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Your starting equation is

    cos(2x) + cos 𝑥 + 1 = 0    (1)


Use  cos(2x) = 2cos^2(x) - 1.   Substitute it into the given equation.  You will get


    (2cos^2(x) - 1) + cos(x) + 1 = 0,   or

     2cos^2(x) + cos(x) = 0.


Factor left side


    (2cos(x) + 1)*cos(x) = 0.


So,  EITHER  cos(x) = 0, giving  x = pi%2F2,  3pi%2F2,


     OR      2cos(x) + 1 = 0,  giving  cos(x) = - 1%2F2,   x = 2pi%2F3,  4pi%2F3.


ANSWER.  The solutions are  pi%2F2,  3pi%2F2,  2pi%2F3,  4pi%2F3.

Solved.



Answer by Solver92311(821) About Me  (Show Source):
You can put this solution on YOUR website!



















John

My calculator said it, I believe it, that settles it

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