Question 1183052:  Find the vertex and Y and X intercepts of the function F(x)=-x^2+4x-3. 
 
is the F(x) considered they y? please and thank you 
 Found 3 solutions by  MathLover1, MathTherapy, josgarithmetic: Answer by MathLover1(20850)      (Show Source):  Answer by MathTherapy(10557)      (Show Source): 
You can  put this solution on YOUR website! Find the vertex and Y and X intercepts of the function F(x)=-x^2+4x-3. 
 
is the F(x) considered they y? please and thank you 
It's NOT NECESSARY, at ALL, to complete the square, as the other person did, in order to get the vertex. 
- x2 + 4x - 3 
The x-coordinate of the vertex is where  , or, where:   
The y-coordinate of the vertex is where   
Therefore, vertex, or   
For the y-intercept, substitute 0 for x, and solve for f(0), or y, as follows:   
                                                                               
For the x-intercepts, substitute 0 for f(x), or y, and solve for x, as follows:   
                                            Substituting 3x + x for 4x gives us:    
                                                                             0 = - x(x - 3) + 1(x - 3) 
                                                                             0 = (- x + 1)(x - 3) 
                                                                             0 = - x + 1     OR      0 = x - 3 
                                                                             x = 1           OR      3 = x ====> x = 3                                                                                
                                                                                 
 Answer by josgarithmetic(39630)      (Show Source): 
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