SOLUTION: A clinical trial tests a method designed to increase the probability of conceiving a girl. In the study 430 babies were born, 344 of them were girls. Use the sample data to constru
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Question 1182979: A clinical trial tests a method designed to increase the probability of conceiving a girl. In the study 430 babies were born, 344 of them were girls. Use the sample data to construct a 99% confidence interval estimate of the percentage of girls born. Based on result, does the method appear to be effective?
( ) < p < ( )
The proportion is different from 0.5? Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! p hat=344/430=0.8
half-interval is z(0.995)*sqrt(.8*.2/430)
=2.575*sqrt(.16/430)
=0.0497
the interval is 0.75 < p < 0.85
Since the interval does not contain 0.5, yes, the proportion is different from 0.5
