Question 1182977: We wish to estimate what percent of adult residents in a certain county are parents.
Out of 100 adult resident sampled, 35 had kids.
Based on this, construct a 99% confidence interval for the proportion p of adult residents who are parents in this county.
Answer in tri-inequality form.
Answer as decimals, to 3 places.
Express the same answer using the point estimate and margin of error.
Answer as decimals, to 3 places.
Answer by Boreal(15235)   (Show Source):
You can put this solution on YOUR website! This is a one-proportion z-interval
half-interval for 99% is z(0.995)*sqrt(p*(1-p)/n)
=2.576*sqrt(0.35*0.65/100)
=0.1228, or 0.123
so the 99%CI is (0.227, 0.477)
or 0.227 < p < 0.473
or 0.35+/-0.123
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