SOLUTION: Karen wants to advertise how many cookie chips are in each Big Chip cookie at her bakery.
She randomly selects a sample of 41 cookies and finds that the number of chocolate chips
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-> SOLUTION: Karen wants to advertise how many cookie chips are in each Big Chip cookie at her bakery.
She randomly selects a sample of 41 cookies and finds that the number of chocolate chips
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Question 1182933: Karen wants to advertise how many cookie chips are in each Big Chip cookie at her bakery.
She randomly selects a sample of 41 cookies and finds that the number of chocolate chips per cookie in the sample has a mean of 14.9 and a standard deviation of 1.3.
What is the 98% confidence interval for the number of chocolate chips per cookie for Big Chip cookies?
Answer accurate to one decimal.
_______ < > _________ Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! 98% CI half t-interval for df=41 is t(0.99,df=40)*s/sqrt(n)=2.423*1.3/sqrt(41)=0.49
(14.4, 15.4) units chocolate chips or 14.4 < mu < 15.4
