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| Question 1182919:  I have been struggling with this problem for a few days now:
 Let
 U	 = 	{1, 2, 3, 4, 5, 6, 7, 8, 9, 10}
 A	 = 	{1, 2, 4, 6}
 B	 = 	{3, 7}
 C	 = 	{1, 3, 6, 7, 9}
 List all the members of the following set.
 A ∩ (B ∪ C)
 
 The class I am taking has no textbooks to reference, so I have been trying to figure this out on my own. I found a similar question with a similar set (where the places of A and C were swapped in the set) on this website, and so I tried the solution and got this as my final answer:
 3,6,7
 The solution basically suggested that you combine the numbers and drop all duplicates (the solution I followed ignores all members of U and only used A, B, and C members).
 The answer, however, is incorrect.
 I am stumped and would appreciate any tips. Thank you!
 So
 Found 4 solutions by  MathLover1, helper 1234321, ikleyn, MathTherapy:
 Answer by MathLover1(20850)
      (Show Source): 
You can put this solution on YOUR website! U = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}
 A = {1, 2, 4, 6}
 B = {3, 7}
 C = {1, 3, 6, 7, 9}
 List all the members of the following set.
 A ∩ (B ∪ C)
 fits find (B ∪ C), all members of the set B or C
 (B ∪ C)={1, 3, 6, 7, 9}=C
 then
 recall:
   so,
 A ∩ (B ∪ C)={1, 2, 4, 6}∩{1, 3, 6, 7, 9}...only common members
 A ∩ (B ∪ C)={1,6}
 
 
Answer by helper 1234321(1)
      (Show Source): Answer by ikleyn(52879)
      (Show Source): 
You can put this solution on YOUR website! . I have been struggling with this problem for a few days now:
 Let
 U = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}
 A = {1, 2, 4, 6}
 B = {3, 7}
 C = {1, 3, 6, 7, 9}
 List all the members of the following set.
 A ∩ (B ∪ C)
 The class I am taking has no textbooks to reference, so I have been trying to figure this out on my own. I found a similar question with a similar set (where the places of A and C were swapped in the set) on this website, and so I tried the solution and got this as my final answer:
 3,6,7
 The solution basically suggested that you combine the numbers and drop all duplicates (the solution I followed ignores all members of U and only used A, B, and C members).
 The answer, however, is incorrect.
 I am stumped and would appreciate any tips. Thank you!
 So
 ~~~~~~~~~~~~
 
 
 
The symbol  B U C  denotes the UNION of two subsets B and C of the universal set U.
The union is the list of all elements belonging to B or C; if some element does belong to both B and C,
we list it ONLY ONCE in the union.
So, the union (B U C) is this set  {1, 3, 6, 7, 9}.
NEXT, we take the INTERSECTION  A ∩ (B ∪ C).
This intersection is the subset, containing elements, common to A and to (B U C).
We list each common element ONLY ONE TIME in the intersection.
So, the intersection is
    A ∩ (B ∪ C) = {1, 6}.
ANSWER.  A ∩ (B ∪ C) = {1, 6}.
Solved, answered and carefully explained.
 
 
 
Answer by MathTherapy(10556)
      (Show Source): 
You can put this solution on YOUR website! I have been struggling with this problem for a few days now:
 Let
 U	 = 	{1, 2, 3, 4, 5, 6, 7, 8, 9, 10}
 A	 = 	{1, 2, 4, 6}
 B	 = 	{3, 7}
 C	 = 	{1, 3, 6, 7, 9}
 List all the members of the following set.
 A ∩ (B ∪ C)
 The class I am taking has no textbooks to reference, so I have been trying to figure this out on my own. I found a similar question with a similar set (where the places of A and C were swapped in the set) on this website, and so I tried the solution and got this as my final answer:
 3,6,7
 The solution basically suggested that you combine the numbers and drop all duplicates (the solution I followed ignores all members of U and only used A, B, and C members).
 The answer, however, is incorrect.
 I am stumped and would appreciate any tips. Thank you!
 So
 
 Yes, elements in set U are NOT factored into your answer for: A ∩ (B ∪ C)A ∩ (B ∪ C)
 ∪ INDICATES UNION, which is: ALL ELEMENTS in BOTH sets, EXCLUDING DUPLICATES
 A ∩ [B + C  -  (B ∩ C)]
 A ∩ (ALL in BOTH sets, or ALL in B & C, EXCLUDING DUPLICATES)
 A      ∩ (ALL in B + ALL in C, less ELEMENTS in BOTH B & C)
 (1, 2, 4, 6) ∩ [(3, 7) + (1, 3, 6, 7, 9)  -  (3, 7)]
 (1, 2, 4, 6) ∩ (1, 3, 6, 7, 9)
 A ∩ (B ∪ C) =
  
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