Question 1182919:  I have been struggling with this problem for a few days now: 
 
Let 
U	 = 	{1, 2, 3, 4, 5, 6, 7, 8, 9, 10} 
A	 = 	{1, 2, 4, 6} 
B	 = 	{3, 7} 
C	 = 	{1, 3, 6, 7, 9} 
List all the members of the following set.  
A ∩ (B ∪ C)
 
 
The class I am taking has no textbooks to reference, so I have been trying to figure this out on my own. I found a similar question with a similar set (where the places of A and C were swapped in the set) on this website, and so I tried the solution and got this as my final answer: 
3,6,7
 
The solution basically suggested that you combine the numbers and drop all duplicates (the solution I followed ignores all members of U and only used A, B, and C members). 
The answer, however, is incorrect. 
 
I am stumped and would appreciate any tips. Thank you! 
So 
 Found 4 solutions by  MathLover1, helper 1234321, ikleyn, MathTherapy: Answer by MathLover1(20850)      (Show Source): 
You can  put this solution on YOUR website! 
 
U = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10} 
A = {1, 2, 4, 6} 
B = {3, 7} 
C = {1, 3, 6, 7, 9} 
List all the members of the following set. 
A ∩ (B ∪ C)
 
fits find (B ∪ C), all members of the set B or C 
(B ∪ C)={1, 3, 6, 7, 9}=C
 
then
 
recall:  
 
so, 
A ∩ (B ∪ C)={1, 2, 4, 6}∩{1, 3, 6, 7, 9}...only common members 
A ∩ (B ∪ C)={1,6}
 
 
 
 Answer by helper 1234321(1)      (Show Source):  Answer by ikleyn(52903)      (Show Source): 
You can  put this solution on YOUR website! . 
I have been struggling with this problem for a few days now: 
Let 
U = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10} 
A = {1, 2, 4, 6} 
B = {3, 7} 
C = {1, 3, 6, 7, 9} 
List all the members of the following set. 
A ∩ (B ∪ C)
 
The class I am taking has no textbooks to reference, so I have been trying to figure this out on my own. I found a similar question with a similar set (where the places of A and C were swapped in the set) on this website, and so I tried the solution and got this as my final answer: 
3,6,7 
The solution basically suggested that you combine the numbers and drop all duplicates (the solution I followed ignores all members of U and only used A, B, and C members). 
The answer, however, is incorrect. 
I am stumped and would appreciate any tips. Thank you! 
So 
~~~~~~~~~~~~
 
 
The symbol  B U C  denotes the UNION of two subsets B and C of the universal set U.
The union is the list of all elements belonging to B or C; if some element does belong to both B and C,
we list it ONLY ONCE in the union.
So, the union (B U C) is this set  {1, 3, 6, 7, 9}.
NEXT, we take the INTERSECTION  A ∩ (B ∪ C).
This intersection is the subset, containing elements, common to A and to (B U C).
We list each common element ONLY ONE TIME in the intersection.
So, the intersection is
    A ∩ (B ∪ C) = {1, 6}.
ANSWER.  A ∩ (B ∪ C) = {1, 6}.
 
Solved, answered and carefully explained.
 
 
 
 
 Answer by MathTherapy(10557)      (Show Source): 
You can  put this solution on YOUR website!  
I have been struggling with this problem for a few days now: 
 
Let 
U	 = 	{1, 2, 3, 4, 5, 6, 7, 8, 9, 10} 
A	 = 	{1, 2, 4, 6} 
B	 = 	{3, 7} 
C	 = 	{1, 3, 6, 7, 9} 
List all the members of the following set.  
A ∩ (B ∪ C)
 
The class I am taking has no textbooks to reference, so I have been trying to figure this out on my own. I found a similar question with a similar set (where the places of A and C were swapped in the set) on this website, and so I tried the solution and got this as my final answer: 
3,6,7
 
The solution basically suggested that you combine the numbers and drop all duplicates (the solution I followed ignores all members of U and only used A, B, and C members). 
The answer, however, is incorrect. 
 
I am stumped and would appreciate any tips. Thank you! 
So 
Yes, elements in set U are NOT factored into your answer for: A ∩ (B ∪ C) 
A ∩ (B ∪ C) 
∪ INDICATES UNION, which is: ALL ELEMENTS in BOTH sets, EXCLUDING DUPLICATES 
             A ∩ [B + C  -  (B ∩ C)] 
             A ∩ (ALL in BOTH sets, or ALL in B & C, EXCLUDING DUPLICATES) 
        A      ∩ (ALL in B + ALL in C, less ELEMENTS in BOTH B & C) 
  (1, 2, 4, 6) ∩ [(3, 7) + (1, 3, 6, 7, 9)  -  (3, 7)] 
  (1, 2, 4, 6) ∩ (1, 3, 6, 7, 9) 
  A ∩ (B ∪ C) =    
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