SOLUTION: A conveyor belt can lift 40 cans per second 3.40 meters up onto a casing floor. If each can has a weight of 5.50 N, what is the power being put out by the electric motor that driv
Algebra ->
Customizable Word Problem Solvers
-> Travel
-> SOLUTION: A conveyor belt can lift 40 cans per second 3.40 meters up onto a casing floor. If each can has a weight of 5.50 N, what is the power being put out by the electric motor that driv
Log On
Question 1182900: A conveyor belt can lift 40 cans per second 3.40 meters up onto a casing floor. If each can has a weight of 5.50 N, what is the power being put out by the electric motor that drives the conveyor Answer by ikleyn(52925) (Show Source):
You can put this solution on YOUR website! .
A conveyor belt can lift 40 cans per second 3.40 meters up onto a casing floor.
If each can has a weight of 5.50 N, what is the power being put out by the electric motor that drives the conveyor ?
~~~~~~~~~~~~~~~
The power P = 40 cans * 3.40 meters up * 5.50 N = 40*3.4*5.5 = 748 joules per second = 748 watts = 0.748 kilowatts. ANSWER
