SOLUTION: A 50 N block is placed on a smooth inclined plane which is 5 meters long and 3 meters high. (a) What force parallel to the plane and applied to the block will keep the block in equ

Algebra ->  Test -> SOLUTION: A 50 N block is placed on a smooth inclined plane which is 5 meters long and 3 meters high. (a) What force parallel to the plane and applied to the block will keep the block in equ      Log On


   

Question 1182844: A 50 N block is placed on a smooth inclined plane which is 5 meters long and 3 meters high. (a) What force parallel to the plane and applied to the block will keep the block in equilibrium? (b) What force is applied by the plane to the block?
Answer by ikleyn(52824) About Me  (Show Source):
You can put this solution on YOUR website!
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(a)  This force is  50*sin(a) = 50%2A%283%2F5%29 = 30 newtons.    ANSWER


     This force is OPPOSITE to the ROLLING force and is directed parallel to the inclined plane.




(b)  This force is  50*cos(a) = 50%2A%284%2F5%29 = 40 newtons.   ANSWER

     This force is called "the REACTION force". It is PERPENDICULAR to the inclined plane.


Solved.     //     All question are answered.

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In my solution,   " a "   is the angle of the inclined plane to horizontal.

        sin(a) = 3%2F5.         cos(a) = sqrt%281-sin%5E2%28a%29%29 = sqrt%281-%283%2F5%29%5E2%29 = 4%2F5.