Question 1182835: In our Condor Cafe, the Oxnard College Culinary Program offers the most delicious and affordable breakfast and lunch choices among the 152 Community Colleges in California.
This week, a random, sample of 359 orders were recorded, and 178 orders were for the $5-meals.
Find the 80% confidence interval for the true proportion of the orders for the $5-meals.
a. Answer as open-interval
b. Express the same answer as a tri-linear inequality using decimals accurate to 3 decimal places
c. Express the same answer using the point estimate and margin of error.
Answer as decimals to 3 places
Answer by Boreal(15235)   (Show Source):
You can put this solution on YOUR website! p hat =178/359=0.4958
80% half-interval is z(0.90)*sqrt(0.4958*0.5042/359); z=1.282
=0.0338
The interval is (0.462, 0.530)
The interval then is 0.462 < mu < 0.530
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0.4958+/- 0.0338 or 0.496+/- 0.034
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