SOLUTION: Assume that a sample is used to estimate a population proportion p.
Find the 99% confidence interval for a sample of size 307 with 196 successes.
Answer as an open-interval (i.e
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Find the 99% confidence interval for a sample of size 307 with 196 successes.
Answer as an open-interval (i.e
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Question 1182771: Assume that a sample is used to estimate a population proportion p.
Find the 99% confidence interval for a sample of size 307 with 196 successes.
Answer as an open-interval (i.e., parentheses) using decimals (not percents) accurate to 3 decimal places.
C.I. = Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! the half-interval is z(0.995)*sqrt(p hat *(1-p hat)/n); p hat = 0.6384
=2.5758*sqrt(0.6384*0.3616/307)
=2.5758*0.0274
=0.0706
(0.568, 0.709)
