SOLUTION: In a survey of 300 randomly selected gun owners, it was found that 75 of them said they owned a gun primarily for protection.
Find the Margin of Error of 95% confidence interval
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Find the Margin of Error of 95% confidence interval
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Question 1182768: In a survey of 300 randomly selected gun owners, it was found that 75 of them said they owned a gun primarily for protection.
Find the Margin of Error of 95% confidence interval for the percentage of all gun owners who would say that they own a gun primarily for protection.
Round all answers to 2 decimal points.
Margin of Error (as a percentage):
Confidence Interval __________% to _____________% Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! proportion p hat is 1/4
95% half-interval (margin of error) is z*sqrt((1/4)*(3/4))/300)
=1.96*sqrt(1/1600)
=0.049 margin of error (4.90%)
(20.10%, 29.90%)
