|
Question 1182640: The amount of coffee that people drink per day is normally distributed with a mean of 17 ounces and a standard deviation of 6 ounces.
18 randomly selected people are surveyed.
Round answers to 4 decimals
What is the distribution of X?
X~N= 17,6
What is the probability that one randomly selected person drinks between 16 and 18 ounces of coffee per day?
For 18 people, find the probability that the average coffee consumption is between 16 and 18 ounces per day.
Find the IQR for the average of 18 coffee drinkers.
Q1= oz
Q2= oz
IQR= oz
Answer by Boreal(15235)   (Show Source):
You can put this solution on YOUR website! X~N(17, 2)); the 2 is the variance/n or sigma^2/n, because it is a distribution of sample means.
The sd is sqrt(2) oz
a. For one person we have -1/6 < z < 1/6, and that probability is 0.1324
b. For 18 people, the SEM is -sqrt(2)/2< z < sqrt (2)/2 and that probability is 0.5206
1/sqrt(2)=sqrt(2)/2
|
|
|
| |
