SOLUTION: Using synthetic division, find one zero of the polynomial f(x)=x^3+c^2-57x+135 then write the polynomial in factored form based on the zero you found:
Zero for the polynomial: f(_
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-> SOLUTION: Using synthetic division, find one zero of the polynomial f(x)=x^3+c^2-57x+135 then write the polynomial in factored form based on the zero you found:
Zero for the polynomial: f(_
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Question 1182631: Using synthetic division, find one zero of the polynomial f(x)=x^3+c^2-57x+135 then write the polynomial in factored form based on the zero you found:
Zero for the polynomial: f(__) = 0
Factors of the polynomial based on the above zero: f(x)= Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! Using synthetic division, find one zero of the polynomial f(x)=x^3+c^2-57x+135
I think this is: f(x) = x^3 + x^2 - 57x + 135
Try the lowest factor of 135, 3
:
.....___________________
3 | 1 + 1 - 57 + 135
............3 + 12 - 135
....--------------------
......1 + 4 - 45 + 0
:
then write the polynomial in factored form based on the zero you found:
(x-3)(x^2 + 4x - 45)
Zero for the polynomial: f(__) = 0
Factor (x^2+4x-45): (x+9)(x-5)
Factors of the polynomial based on the above zero:
f(x)= (x-3)(x-5)(x+9)
