SOLUTION: The point P has coordinates (a,b). Another point Q is formed by reversing the coordinates of P, i.e. Q has coordinates (b,a). (i) Show that PQ is perpendicular to the line y=x. (

Algebra ->  Length-and-distance -> SOLUTION: The point P has coordinates (a,b). Another point Q is formed by reversing the coordinates of P, i.e. Q has coordinates (b,a). (i) Show that PQ is perpendicular to the line y=x. (      Log On


   



Question 1182583: The point P has coordinates (a,b). Another point Q is formed by reversing the coordinates of P, i.e. Q has coordinates (b,a).
(i) Show that PQ is perpendicular to the line y=x.
(ii) Show that the midpoint, M, of PQ lies on y=x.

Answer by ikleyn(52794) About Me  (Show Source):
You can put this solution on YOUR website!
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The point P has coordinates (a,b). Another point Q is formed by reversing the coordinates of P,
i.e. Q has coordinates (b,a).
(i) Show that PQ is perpendicular to the line y=x.
(ii) Show that the midpoint, M, of PQ lies on y=x.
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            In this problem, it is assumed that a =/= b --- otherwise, the statement loses sense.
            So, I will assume that a =/= b,  although the problem does not says it explicitly.


                        Part  ( i )


Let's compare slopes of the line y = x  and the line (segment) PQ.


The line y = x has the slope equal to 1, OBVIOUSLY.


The segment PQ hs the slope  m = increment_y%2Fincrement_x = %28a-b%29%2F%28b-a%29 = -1.


The slopes 1 and -1 are negatively reciprocal: 1*(-1) = -1; THEREFORE, the line y = x and the segment (the line) PQ are perpendicular.


Thus the first statement is proved.


                        Part  ( ii )

The coordinates of the midpoint are  (%28a%2Bb%29%2F2,%28a%2Bb%29%2F2).


Both x- and y- coordinates are equal.


It proves, that the midpoint lies on the line y = x.


Thus the second statement is proved,  too.


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The points  P  and  Q  are mirror reflections each other about the line   y = x.