SOLUTION:
How do you slove this problem: the 4th root of (x-5) to the 8th power?
i need help with the steps so i can see how its done. thanks.
Algebra ->
Square-cubic-other-roots
-> SOLUTION:
How do you slove this problem: the 4th root of (x-5) to the 8th power?
i need help with the steps so i can see how its done. thanks.
Log On
How do you slove this problem: the 4th root of (x-5) to the 8th power?
i need help with the steps so i can see how its done. thanks. Found 2 solutions by stanbon, checkley71:Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! How do you solve this problem: the 4th root of (x-5) to the 8th power?
---------
4th root of (x-5)^8 = (x-5)^(8/4) = (x-5)^2
= x^2-10x+25
===================
Cheers,
Stan H.
You can put this solution on YOUR website! 4throot(x-5)^8=4throot[(x-5)^4(x-5)^4]=(x-5)(x-5)=x^2-10x+25 answer.
proof:
letx=7:
4throot(7-5)^8=4throot(2)^8=4throot256=4 answer.
7^2-10*7+25=49-70+25=74-70=4 answer.