SOLUTION: A random variable has a Poisson distribution such that P(X = 1) = P(X = 2).
Compute:
a. The mean of X
b. P (X = 3)
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-> SOLUTION: A random variable has a Poisson distribution such that P(X = 1) = P(X = 2).
Compute:
a. The mean of X
b. P (X = 3)
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Question 1182480: A random variable has a Poisson distribution such that P(X = 1) = P(X = 2).
Compute:
a. The mean of X
b. P (X = 3) Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! p(x=1) is e^(-lambda)*lambda^1/1
p(x=2) is e^(-lambda)*lambda^2/2
Those are equal, so 2lambda ^1=lambda^2
lambda=2
e^(-2)*2=e(-2)*2^2/2
mean is 2.
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probability x=3 is e^(-2)*8/6=0.1804
