Question 1182443: What is the momentum of a fuel tanker moving to the west that has a loaded tonnage of 800000 tons
( lets use metric tons .. 1 ton = 1000 kg ) and a speed of 36.0 mph in kg*m/s
Found 4 solutions by mananth, ikleyn, CPhill, n2:
Answer by mananth(16949)   (Show Source):
You can put this solution on YOUR website!
loaded tonnage of 800000 tons
800000*1000 = 8*10^8 kg
speed = 26 mph
1 mph = 0.477 m/s
Momentum P = m * v
P= 8*10^8 * 0.477
= 381600000 kg.m/s
Answer by ikleyn(53619)  (Show Source):
You can put this solution on YOUR website! .
What is the momentum of a fuel tanker moving to the west that has a loaded tonnage of 800000 tons
( lets use metric tons .. 1 ton = 1000 kg ) and a speed of 36.0 mph in kg*m/s
~~~~~~~~~~~~~~~~~~~~~~~~~
Calculations in the post by @mananth are TOTALLY and FATALLY incorrect
I came to bring a correct solution.
loaded tonnage of 800000 tons
800000*1000 = 8*10^8 kg
speed = 36 mph
1 mile = 1609.34 meters
Momentum P = m * v
P=  = 12,874,720,000 kg.m/s
Solved correctly, properly and accurately.
Answer by CPhill(2189)  (Show Source):
You can put this solution on YOUR website! loaded tonnage of 800000 tons
800000*1000 = 8*10^8 kg
speed = 26 mph
1 mph = 0.477 m/s
Momentum P = m * v
P= 8*10^8 * 0.477
= 381600000 kg.m/s
Answer by n2(55)  (Show Source):
You can put this solution on YOUR website! .
Yesterday (Jan.19, 2026) I witnessed strange behavior from @CPhill on this forum.
A few days ago I refuted an incorrect solution provided by @mananth at this spot.
@mananth's solution was incorrect because he incorrectly converted miles per hour to meters per second,
and, in addition, lost a factor of 36 (36 miles per hour) in his solution.
As a result, @mananth's solution had nothing in common with the correct solution - which is why
I redid/corrected/fixed it.
Now @CPhill has copied and reposted this incorrect solution by @mananth again.
This is not the only such action by @CPhill.
Yesterday, @CPhill made several (about 15) other similar actions of the same kind with other posts
where I refuted @mananth's solutions.
I consider these @CPhyll's actions to be wrong, leading to a distortion of the truth on this forum.
Therefore, I strongly protest against such actions by @CPhill and consider it necessary that visitors
to this forum be aware of this.
I recommend to a reader to ignore the post by @CPhill.
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