SOLUTION: Determine whether the set of ordered pairs is a function. {(−8, 3), (3, 5), (5, 6), (6, 8)} function not a function State the domain and range. (Enter your answers as c

Algebra ->  Coordinate-system -> SOLUTION: Determine whether the set of ordered pairs is a function. {(−8, 3), (3, 5), (5, 6), (6, 8)} function not a function State the domain and range. (Enter your answers as c      Log On


   



Question 1182384: Determine whether the set of ordered pairs is a function.
{(−8, 3), (3, 5), (5, 6), (6, 8)}
function
not a function
State the domain and range. (Enter your answers as comma-separated lists.)
domain



range



Found 3 solutions by MathLover1, Theo, ikleyn:
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

By definition, the inputs in a function have only one output.
if each element in the domain is matched with exactly one element in the range, you have a function
{(-8, 3), (3, 5), (5, 6), (6,+8)}

(-8, 3)->-8 matched with 3
(3, 5)->3 matched with 5
(5, 6)->5 matched with 6
(6,+8)->6 matched with 8
=>each element value of x is matched with exactly one y, you have a function
domain: -8,3,5,6
range:3,5,6, 8



Answer by Theo(13342) About Me  (Show Source):
You can put this solution on YOUR website!

here's a reference for the definiition of a function.

https://www.purplemath.com/modules/fcns.htm

the definition is that, for each and every value of x, there can be one and only one value of y.

if you have more than one value of y for any value of x, then the relation is not a function.

the point pairs in this problem can be graphed as shown below:

with these point pairs, it is clear that any value of x in the set points to one and only one value of y, therefore the relation is a function.


Answer by ikleyn(52817) About Me  (Show Source):
You can put this solution on YOUR website!
.


In this problem, the input values  (the arguments of a function)  are

                -8,   3,   5   and   6.



These values are  ALL  D I F F E R E N T;     T H E R E F O R E,  the question   " is it a function or not "

                    even  CAN  NOT  arise:   surely,  it is a function.



Questions may arise if and only if some input values are identical.

                    (which is not the case in this problem).