SOLUTION: The average price of a personal computer(PC) is $949. If the computer prices are approximately normally distributed and the population standard deviation is $100, what is the proba

Algebra ->  Probability-and-statistics -> SOLUTION: The average price of a personal computer(PC) is $949. If the computer prices are approximately normally distributed and the population standard deviation is $100, what is the proba      Log On


   

Question 1182336: The average price of a personal computer(PC) is $949. If the computer prices are approximately normally distributed and the population standard deviation is $100, what is the probability that a randomly selected PC costs more than $1200? (Please answer in decimal and round the answer to three decimal places)
Answer by Theo(13342) About Me  (Show Source):
You can put this solution on YOUR website!
average (mean) is 949
standard deviation is 100
you want to find the probability that a randomly selected computer costs more than 1200.

z-score = (x - m) / s
x is the raw score
m is the mean
s is the standard deviation

formula becomes:

z = (1200 - 949) / 100 = 2.51

probability of a price greater than that would be .0060365747 = .006 rounded to 3 decimal places.