SOLUTION: Given triangle ABC, if csc A=13/7, then what is the exact value of cos A in fraction form. Include a labeled sketch.

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Question 1182302: Given triangle ABC, if csc A=13/7, then what is the exact value of cos A in fraction form. Include a labeled sketch.
Answer by ikleyn(52803) About Me  (Show Source):
You can put this solution on YOUR website!
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Given triangle ABC, if csc A=13/7, then what is the exact value of cos A in fraction form.
Include a labeled sketch.
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If csc(A) = 13%2F7,  then  sin(A) = 7%2F13  and  


    cos(A) = +/- sqrt%281-+%287%2F13%29%5E2%29 = +/- sqrt%281-+49%2F169%29 = +/- sqrt%28%28169-49%29%2F169%29 = +/- sqrt%28120%29%2F13 = +/- %282%2Asqrt%2830%29%29%2F13.      ANSWER

Solved.


Regarding the plot, make it on your own. (Two plots are possible).


This forum is not an art studio to make plots on your requests.