Question 1182281: Three identical rectangles are put together to form a bigger rectangle ABCD,
as shown below. Given that the length of the shorter side of each of the
smaller rectangles is 5 feet, what is the area in square feet of the
rectangle ABCD?
Found 2 solutions by Edwin McCravy, mccravyedwin:
Answer by Edwin McCravy(20056)   (Show Source):
Answer by mccravyedwin(407)  (Show Source):
You can put this solution on YOUR website!
Since FE is made up of two shorter sides, and
each is 5 feet, the longer side of each rectangle
is 2 times 5 feet or 10 feet.
Each rectangle is 10 feet by 5 feet.
So the area of each one is 10x5 = 50 square feet.
Since there are 3 of them, we multiply 50x3 and
get 150 square feet.
You can also get the same answer by multiplying
the longer side of the big rectangle, which is 15,
by the shorter side of the big rectangle, which is
10, and get the same answer. 15x10 = 150 square feet.
Edwin
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