SOLUTION: An airplane traveled 2660 miles in 3.5 hours with a tail wind. The return trip took 3.8 hours with a head wind. What was the speed of the airplane in still air? What was the spe
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Question 118215: An airplane traveled 2660 miles in 3.5 hours with a tail wind. The return trip took 3.8 hours with a head wind. What was the speed of the airplane in still air? What was the speed of the wind? Solve by using a system oi\f equations. Found 2 solutions by stanbon, checkley71:Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! An airplane traveled 2660 miles in 3.5 hours with a tail wind.
The return trip took 3.8 hours with a head wind.
What was the speed of the airplane in still air?
What was the speed of the wind?
Solve by using a system oi\f equations
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Let airplane speed be "p"; Let wind speed be "w"
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With-the-wind DATA:
Distance = 2660 mi ; Time = 3.5 hrs ; Rate = d/t = 2660/3.5 = 760 mph
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Against-the-wind DATA:
Distance = 2660 mi; Time = 3.8 hrs ; Rate = d/t = 2660/3.8 = 700 mph
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EQUATIONS:
p+w = 760
P-w = 700
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Add to get:
2p = 1460
p = 730 mph (speed of the place in still air)
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Solve for "w":
p+w = 760
730+w = 760
w = 30 mph (speed of the wind)
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Cheers,
Stan H.
You can put this solution on YOUR website! 2660/3.5=760 MPH FOR THE ORIGINAL TRIP
2660/3.8=700 MPH FOR THE RETURN TRIP
760-W=700=W
-2X=-60
X=-60/-2
X=30 MPH FOR THE WIND.
760-30=730 MPH FOR THE PLANE IN STILL AIR.
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