You can
put this solution on YOUR website! .
Please help with the homework. Solve the following using quadratic equation
(x+1)(x-2)+(x+2)(x+1)=2(3x-1)
~~~~~~~~~~~~~~~~~~
The left side is (trace my transformations)
(x+1)*(x-2) + (x+2)(x+1) = take the common factor (x+1) out the parenteses =
= (x+1)*(x-2 + x+2) = (x+1)*(2x).
So, the equation takes the form
2x*(x+1) = 2*(3x-1)
Cancel common factor 2 in both sides
x*(x+1) = 3x-1
Simplify
x^2 + x = 3x -1
x^2 - 2x + 1 = 0
(x-1)^2 = 0
The only solution is x= 1.
ANSWER. The given equation has a unique solution x= 1.
Solved.
