SOLUTION: To solve the equation 4^x+6=32^6x-5 , equivalent powers with base 2 could be found, and then the exponents could be equated to give the equation

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Question 1181883: To solve the equation 4^x+6=32^6x-5 , equivalent powers with base 2 could be found, and then the exponents could be equated to give the equation
Found 2 solutions by ikleyn, greenestamps:
Answer by ikleyn(52884) About Me  (Show Source):
You can put this solution on YOUR website!
.

True.


It is correct.



Answer by greenestamps(13209) About Me  (Show Source):
You can put this solution on YOUR website!


The statement of the problem is incomplete, or else uses bad grammar.

"...and then the exponents could be equated to give the equation"

What is that supposed to mean?!

Presumably the problem was about expressing 4 and 32 as powers of 2 to solve the given equation for x.

But the equation as you show it can NOT be solved simply by expressing 4 and 32 as powers of 2.

"4^x+6=32^6x-5"

Here is how the program on this website interprets that: 4%5Ex%2B6=32%5E6x-5

I was a bit surprised by that interpretation; I thought it would be interpreted as "4^x+6=32^(6x)-5" = 4%5Ex%2B6=32%5E%286x%29-5

But neither of those interpretations allows for solving for x just by expressing 4 and 32 as powers of 2.

The trouble with your post is that you were very sloppy in your use of parentheses (or the absence of your use of them).

If the equation is to be solved for x by expressing 4 and 32 as powers of 2, then the given equation MUST read "4^(x+6)=32^(6x-5)" --> 4%5E%28x%2B6%29=32%5E%286x-5%29

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In the end, I have no idea if I have helped you with your question, because I can't determine from your post what the question was....

If you post a problem wanting to get help with it, take the time to make sure you have presented the problem correctly before you post it.