SOLUTION: If sin theta=0.6157 and 90° < theta < 360°, then theta, to the nearest degree, is Select one: a. 218 degree b. 142 degree c. 38 degree d. 128 degree

Algebra ->  Trigonometry-basics -> SOLUTION: If sin theta=0.6157 and 90° < theta < 360°, then theta, to the nearest degree, is Select one: a. 218 degree b. 142 degree c. 38 degree d. 128 degree       Log On


   



Question 1181864: If sin theta=0.6157 and 90° < theta < 360°, then theta, to the nearest degree, is
Select one:
a. 218 degree
b. 142 degree
c. 38 degree
d. 128 degree

Found 2 solutions by ikleyn, Solver92311:
Answer by ikleyn(52914) About Me  (Show Source):
You can put this solution on YOUR website!
.
If sin theta=0.6157 and 90°, then theta, to the nearest degree, is
Select one:
a. 218 degree
b. 142 degree
c. 38 degree
d. 128 degree
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Your post is incomplete.

Some vitally important part is missed.

Without it, the problem CAN NOT be solved and the question CAN NOT be answered.


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As I see, John changed / edited the original post by an arbitrary way without even announcing it . . .

It is just out of any game's rules . . .



By the way, it is how the Chernobyl reactor was blown up - they played with it out the rules . . .




Answer by Solver92311(821) About Me  (Show Source):
You can put this solution on YOUR website!


Since QI is eliminated, and the sine is negative in QIII and QIV, must lie in QII. Answer a is in QIII, and answer c is in QI, so those two are eliminated. Use your calculator to find and subtract that from 180°.

John

My calculator said it, I believe it, that settles it

From
I > Ø