SOLUTION: Which polynomial is prime? 3x3 + 3x2 - 2x - 2 3x3 - 2x2 + 3x - 4 4x3 + 2x2 + 6x + 3 4x3 + 4x2 - 3x - 3

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: Which polynomial is prime? 3x3 + 3x2 - 2x - 2 3x3 - 2x2 + 3x - 4 4x3 + 2x2 + 6x + 3 4x3 + 4x2 - 3x - 3       Log On


   

Question 1181839: Which polynomial is prime?
3x3 + 3x2 - 2x - 2
3x3 - 2x2 + 3x - 4
4x3 + 2x2 + 6x + 3
4x3 + 4x2 - 3x - 3

Answer by greenestamps(13200) About Me  (Show Source):
You can put this solution on YOUR website!


None of those are prime. Three of them can be easily factored by grouping.

3x^3 + 3x^2 - 2x - 2 = (3x^2)(x+1)-2(x+1) : (x+1) is a factor

3x^3 - 2x^2 + 3x - 4 : x=1 makes the expression equal to 0, so (x-1) is a factor

4x^3 + 2x^2 + 6x + 3 = (2x^2)(2x+1)+3(2x+1) : (2x+1) is a factor

4x^3 + 4x^2 - 3x - 3 =4x^2(x+1)-3(x+1) : (x+1) is a factor