SOLUTION: A sphere of radius 6.87 in. rests in a circular hole of radius 5.13 in. How far below the plane of the hole does the sphere extend?
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Question 1181728: A sphere of radius 6.87 in. rests in a circular hole of radius 5.13 in. How far below the plane of the hole does the sphere extend? Answer by Solver92311(821) (Show Source):
Let represent the measure of the radius of the sphere and represent the measure of the radius of the circular hole. If you chose an instance of the sphere's radius that intersects the circle and an instance of the circle's radius that intersects the endpoint of the chosen sphere radius, you form a right triangle with hypotenuse and one leg that measures . By Pythagoras, the other side, namely the portion of a radius above the circular hole, is , hence the desired distance is
John
My calculator said it, I believe it, that settles it
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