Question 1181640: The distance between two towns A and B, is 90 km. John cycles from A to B whereas Harry
cycles from B to A. They start cycling towards each other at the same time.John cycles twice
as fast as Harry does. If they meet 2 hours later, at what average speed is each cyclist traveling?
Answer by htmentor(1343)   (Show Source):
You can put this solution on YOUR website! Let h = Harry's speed, and j = John's speed
Then their relative speed, traveling toward each other is h + j
Since they travel 90 km in 2 h, we can equate their relative speed to 90/2 [km/h]
Since, j = 2h, we have
3h = 45 -> h = 15 km/h
Thus Harry's speed is 15 km/h and John's is 30 km/h
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