SOLUTION: A distribution of values is normal with a mean of 199.9 and a standard deviation of 82.
Find P57, which is the score separating the bottom 57% from the top 43%.
P57 =
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-> SOLUTION: A distribution of values is normal with a mean of 199.9 and a standard deviation of 82.
Find P57, which is the score separating the bottom 57% from the top 43%.
P57 =
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Question 1181628: A distribution of values is normal with a mean of 199.9 and a standard deviation of 82.
Find P57, which is the score separating the bottom 57% from the top 43%.
P57 =
Enter your answer as a number accurate to 4 decimal places. Answer by Theo(13342) (Show Source):
You can put this solution on YOUR website! mean = 199.9
standard deviation = 82
p57 = area to the left of the z-score.
z-score with area to the left of it equal to .57 = .1763741565 = (
use the z-score formula to find the raw swcore.
z = (x - m) / sd
z is the z-score
x is the raw score
m is the mean
sd is the standard deviation
formula becomes:
.1763741565 = (x - 199.9) / 82
solve for x to get:
x = 82 * .1763741565 + 199.9 = = 214.3626808
round your answer to 4 decimal places to get:
x = 214.3627
this is the raw score that has 57% of the area under the normal distribution curve to the left of it and 43% of the area under the normal distribution curve to the right of it.
