SOLUTION: Elimination Method OR Substitution OR Substitution-Equal Values Method 1.y=3x-2 y=x+4 2.5x-4y=27 3x+4y=29 3.2x+5y=25 y=x+4
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-> SOLUTION: Elimination Method OR Substitution OR Substitution-Equal Values Method 1.y=3x-2 y=x+4 2.5x-4y=27 3x+4y=29 3.2x+5y=25 y=x+4
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Question 1181622
:
Elimination Method OR Substitution OR Substitution-Equal Values Method
1.y=3x-2
y=x+4
2.5x-4y=27
3x+4y=29
3.2x+5y=25
y=x+4
Answer by
greenestamps(13200)
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1. y=3x-2
y=x+4
The given is two different expressions both equal to y.
Use what you are apparently calling Substitution-Equal Values Method:
3x-2 = x+4
...
2. 5x-4y=27
3x+4y=29
The given has one equation with "-4y" and the other with "+4y".
Clearly, use Elimination Method:
8x = 56
...
3. 2x+5y=25
y=x+4
The given has one in standard form Ax+By=C; the other is in "y=" form.
Clearly, use Substitution Method
2x+5(x+4)=25
...