SOLUTION: The remainder, when 5x^3-6x^2=4x-5 is divided by x+1, is Select one: a. 2 b. 20 c. -20 d. -2

Algebra ->  Trigonometry-basics -> SOLUTION: The remainder, when 5x^3-6x^2=4x-5 is divided by x+1, is Select one: a. 2 b. 20 c. -20 d. -2       Log On


   

Question 1181483: The remainder, when 5x^3-6x^2=4x-5 is divided by x+1, is
Select one:
a. 2
b. 20
c. -20
d. -2

Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
This is an equation: 5x%5E3-6x%5E2=4x-5

5x%5E3-6x%5E2-4x%2B5=0----------this is a polynomial, from the given equation.

Dividing it by x+1 is same as checking for "root" of -1. (You could use synthetic division.)
-1  |  5   -6   -4   5
    |     -5     11  -7
    |______________________
       5  -11    7    highlight%28-2%29

Answer by ikleyn(52786) About Me  (Show Source):
You can put this solution on YOUR website!
.
The remainder, when 5x^3-6x^2=4x-5 is divided by x+1, is
Select one:
a. 2
b. 20
c. -20
d. -2
~~~~~~~~~~~~~~


In your post,  the polynomial is written FATALLY INCORRECTLY;
therefore,  the post makes no sense.


Ignore the answer by  @josgarithmetic,  which is  NOT  ADEQUATE  to the situation.


Re-post in correct form.