SOLUTION: Do the following exercises. It is very important to draw a diagram for each problem and label the horizontal and vertical components of the variables. 2. A missile is fired with a

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Question 1181323: Do the following exercises. It is very important to draw a diagram for each problem and label the horizontal and vertical components of the variables.
2. A missile is fired with an initial velocity of 85m/s at an angle 30° from the horizontal.
a. After how many seconds will the missile reach its highest point?
b. What is the maximum height reached by the missile?
Calculate the total horizontal distance travelled by the missile after it hits the ground. This is called the Range.
This is not related to algebra but I hope someone can help me. Thank you😊

Found 2 solutions by ikleyn, Solver92311:
Answer by ikleyn(52794) About Me  (Show Source):
You can put this solution on YOUR website!
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3 - 4 days ago I solved  TWIN  problem at this forum,  see the link

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Answer by Solver92311(821) About Me  (Show Source):
You can put this solution on YOUR website!

.

The horizontal velocity does not affect the height of the projectile. The two vectors of interest when considering the height are the vertical acceleration vector which is equal to the acceleration due to the force of gravity, namely -9.8 meters per second squared (negative because the force is downward), and the vertical component of the initial velocity vector, namely . Presuming the missile is launched at ground level and assuming a missile ideal length of zero, the following quadratic models the instantaneous height at seconds after launch:



Divide the additive inverse of the first-degree term coefficient by the second-degree term coefficient to find the value of the independent variable at the vertex of the parabola. The fact that the lead coefficient is negative ensures that this is the time value at the maximum height.

The maximum height reached is the value of the height function at the time calculated in the first part of the problem.

The horizontal distance is a function of the horizontal component of the initial velocity vector and the horizontal acceleration vector. Since the horizontal acceleration vector has a magnitude of zero, the only relevant values are the total time of flight which is the non-zero root of the height function set to zero, and the horizontal component of the initial velocity. The magnitude of the horizontal component of the initial velocity vector is . The horizontal distance traveled is then:




You can do your own arithmetic.

John

My calculator said it, I believe it, that settles it

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